What is ln((\sqrt[3]{y^2+6})/(e^2)) ?

The solution to ln((\sqrt[3]{y^2+6})/(e^2)) is ln(\sqrt[3]{y^2+6})-2

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simplify ln((\sqrt[3]{y^2+6})/(e^2))

simplify

Solution steps

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{2}) = 2 ln (e)

2 ln (e) = 2

\frac{1}{2} [ln (x + 3) + ln (x) - ln (x^{2} - 1)]

- lo g_{10} (4.18 \cdot 1 0^{- 4})

3 lo g_{10} (d) - lo g_{10} (k)

lo g_{4} (u^{3} v^{6})

lo g_{10} (\frac{2 x}{7})

What is ln((\sqrt[3]{y^2+6})/(e^2)) ?
The solution to ln((\sqrt[3]{y^2+6})/(e^2)) is ln(\sqrt[3]{y^2+6})-2