What is log_{10}(2x)+log_{10}(3y) ?

The solution to log_{10}(2x)+log_{10}(3y) is log_{10}(6xy)

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simplify log_{10}(2x)+log_{10}(3y)

simplify

lo g_{10} (2 x) + lo g_{10} (3 y)

lo g_{10} (6 x y)

Solution steps

lo g_{10} (2 x) + lo g_{10} (3 y)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (2 x) + lo g_{10} (3 y) = lo g_{10} (2 x \cdot 3 y)

= lo g_{10} (2 x \cdot 3 y)

Simplify

2 x \cdot 3 y : 6 x y

= lo g_{10} (6 x y)

ln ∣ 321180 ∣ - ln ∣ 101000 ∣

lo g_{2} (9 x^{3})

lo g_{3} (0.0994) + lo g_{3} (4.5497)

lo g_{a} (8) + lo g_{a} (5) + 2 lo g_{a} (2)

lo g_{b} (m \cdot n)

What is log_{10}(2x)+log_{10}(3y) ?
The solution to log_{10}(2x)+log_{10}(3y) is log_{10}(6xy)