What is ln((7+e^x)/(7-e^x)) ?

The solution to ln((7+e^x)/(7-e^x)) is ln(7+e^x)-ln(7-e^x)

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simplify ln((7+e^x)/(7-e^x))

simplify

ln (\frac{7 + e ^{x}}{7 - e ^{x}})

ln (7 + e^{x}) - ln (7 - e^{x})

Solution steps

ln (\frac{7 + e ^{x}}{7 - e ^{x}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{7 + e ^{x}}{7 - e ^{x}}) = ln (7 + e^{x}) - ln (7 - e^{x})

= ln (e^{x} + 7) - ln (- e^{x} + 7)

\frac{1}{2} ln (\frac{1}{4})

20 \cdot lo g_{10} (4 \cdot 3.1415 \cdot x \cdot (8.16))

lo g_{2} (3 a)

ln (\frac{1}{b - a})

3 lo g_{10} (2) - lo g_{10} (5)

What is ln((7+e^x)/(7-e^x)) ?
The solution to ln((7+e^x)/(7-e^x)) is ln(7+e^x)-ln(7-e^x)