What is log_{b}(24)-log_{b}(8) ?

The solution to log_{b}(24)-log_{b}(8) is log_{b}(3)

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simplify log_{b}(24)-log_{b}(8)

simplify

lo g_{b} (24) - lo g_{b} (8)

lo g_{b} (3)

Solution steps

lo g_{b} (24) - lo g_{b} (8)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{b} (24) - lo g_{b} (8) = lo g_{b} (\frac{24}{8})

= lo g_{b} (\frac{24}{8})

Divide the numbers:

\frac{24}{8} = 3

= lo g_{b} (3)

lo g_{10} (4) - lo g_{10} (24)

f (x) = lo g_{10} (3 x + 9) + lo g_{10} (x + 8)

lo g_{\frac{1}{3}} (3 x)

ln (5) - ln (20)

10 lo g_{10} (2) + lo g_{10} (3) - 3 lo g_{10} (4)

What is log_{b}(24)-log_{b}(8) ?
The solution to log_{b}(24)-log_{b}(8) is log_{b}(3)