What are the solutions to the equation x^2-2x-4=4 ?

The solutions to the equation x^2-2x-4=4 are x=4,x=-2

Find the zeros of x^2-2x-4=4

The zeros of x^2-2x-4=4 are x=4,x=-2

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x^{2} - 2 x - 4 = 4

x = 4, x = - 2

Solution steps

x^{2} - 2 x - 4 = 4

Move

4

to the left side

x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

x = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

x^{2} - 11 x > 0

0.5 x^{2} + 2.375 x \leq 0.625

lo g_{\frac{1}{2}} (\frac{1}{4})

3 n^{2} - n = 14

2 x - 31 = 3 (x + 2)

What are the solutions to the equation x^2-2x-4=4 ?
The solutions to the equation x^2-2x-4=4 are x=4,x=-2
Find the zeros of x^2-2x-4=4
The zeros of x^2-2x-4=4 are x=4,x=-2