What is 5log_{4}(x)+1/4 log_{4}(y)-2 ?

The solution to 5log_{4}(x)+1/4 log_{4}(y)-2 is log_{4}(x^5y^{1/4})-2

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simplify 5log_{4}(x)+1/4 log_{4}(y)-2

simplify

5 lo g_{4} (x) + \frac{1}{4} lo g_{4} (y) - 2

lo g_{4} (x^{5} y^{\frac{1}{4}}) - 2

Solution steps

5 lo g_{4} (x) + \frac{1}{4} lo g_{4} (y) - 2

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

5 lo g_{4} (x) = lo g_{4} (x^{5})

= lo g_{4} (x^{5}) + \frac{1}{4} lo g_{4} (y) - 2

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{4} lo g_{4} (y) = lo g_{4} (y^{\frac{1}{4}})

= lo g_{4} (x^{5}) + lo g_{4} (y^{\frac{1}{4}}) - 2

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{4} (x^{5}) + lo g_{4} (y^{\frac{1}{4}}) = lo g_{4} (x^{5} y^{\frac{1}{4}})

= lo g_{4} (x^{5} y^{\frac{1}{4}}) - 2

\frac{600}{e ^{\frac{2 l n ( 5 )}{13}}}

5 ln (x + 5) - 3 ln (x)

lo g_{9} (x (x - 10))

lo g_{6} (x z)

lo g_{10} (\frac{1 - x}{1 + x})

What is 5log_{4}(x)+1/4 log_{4}(y)-2 ?
The solution to 5log_{4}(x)+1/4 log_{4}(y)-2 is log_{4}(x^5y^{1/4})-2