What is ((6mn^{-2})/(3m^{-1)n^2})^{-3} ?

The solution to ((6mn^{-2})/(3m^{-1)n^2})^{-3} is (n^{12})/(8m^6)

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simplify ((6mn^{-2})/(3m^{-1)n^2})^{-3}

simplify

(\frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}})^{- 3}

\frac{n ^{12}}{8 m ^{6}}

Solution steps

(\frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}})^{- 3} = \frac{1}{( \frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}} ) ^{3}}

= \frac{1}{( \frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}} ) ^{3}}

Simplify

(\frac{6 m n ^{- 2}}{3 m ^{- 1} n ^{2}})^{3} : \frac{8 m ^{6}}{n ^{12}}

= \frac{1}{\frac{8 m ^{6}}{n ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{n ^{12}}{8 m ^{6}}

\frac{1}{12} - \frac{5}{12}

52 7^{2} + 32 0^{2} = x^{2}

\frac{10}{3 n - 4} - \frac{5}{4 - 3 n}

x + 5 = 11

\frac{2}{5} - \frac{2}{3}

What is ((6mn^{-2})/(3m^{-1)n^2})^{-3} ?
The solution to ((6mn^{-2})/(3m^{-1)n^2})^{-3} is (n^{12})/(8m^6)