What is log_{10}(7)+log_{10}(12)-log_{10}(3) ?

The solution to log_{10}(7)+log_{10}(12)-log_{10}(3) is log_{10}(28)

Popular >

simplify log_{10}(7)+log_{10}(12)-log_{10}(3)

simplify

lo g_{10} (7) + lo g_{10} (12) - lo g_{10} (3)

lo g_{10} (28)

Decimal Notation

1.44715 \dots

Solution steps

lo g_{10} (7) + lo g_{10} (12) - lo g_{10} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (7) + lo g_{10} (12) = lo g_{10} (7 \cdot 12)

= lo g_{10} (7 \cdot 12) - lo g_{10} (3)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (7 \cdot 12) - lo g_{10} (3) = lo g_{10} (\frac{7 \cdot 12}{3})

= lo g_{10} (\frac{7 \cdot 12}{3})

Cancel

\frac{7 \cdot 12}{3} : 28

= lo g_{10} (28)

\frac{1}{4} ln (\frac{x ^{4} y ^{7}}{z ^{5}})

lo g_{10} (28) - lo g_{10} (14)

6 lo g_{10} (5) - lo g_{10} (2) - 3 lo g_{10} (3)

lo g_{4} (p^{2}) - lo g_{4} (4 q)

ln (34) ln (17)

What is log_{10}(7)+log_{10}(12)-log_{10}(3) ?
The solution to log_{10}(7)+log_{10}(12)-log_{10}(3) is log_{10}(28)