What is log_{10}((27)/y) ?

The solution to log_{10}((27)/y) is 3log_{10}(3)-log_{10}(y)

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simplify log_{10}((27)/y)

simplify

lo g_{10} (\frac{27}{y})

3 lo g_{10} (3) - lo g_{10} (y)

Solution steps

lo g_{10} (\frac{27}{y})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{27}{y}) = lo g_{10} (27) - lo g_{10} (y)

= lo g_{10} (27) - lo g_{10} (y)

lo g_{10} (27) = 3 lo g_{10} (3)

= 3 lo g_{10} (3) - lo g_{10} (y)

0.935 - \frac{0.592}{2} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

f (x) = ln (\frac{3 ^{x} 6 ^{3 x}}{2 ^{2 x}})

lo g_{b} (\frac{x y ^{3}}{w ^{3} z})

\frac{1}{5} ln (\frac{5}{4})

- ln (\frac{5}{9})

What is log_{10}((27)/y) ?
The solution to log_{10}((27)/y) is 3log_{10}(3)-log_{10}(y)