What is log_{3}(3-x)+log_{3}(4-x) ?

The solution to log_{3}(3-x)+log_{3}(4-x) is log_{3}((3-x)(4-x))

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simplify log_{3}(3-x)+log_{3}(4-x)

simplify

lo g_{3} (3 - x) + lo g_{3} (4 - x)

lo g_{3} ((3 - x) (4 - x))

Solution steps

lo g_{3} (3 - x) + lo g_{3} (4 - x)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{3} (3 - x) + lo g_{3} (4 - x) = lo g_{3} ((- x + 3) (- x + 4))

= lo g_{3} ((3 - x) (4 - x))

lo g_{10} (\frac{y}{z ^{2}})

\frac{1}{5} [20 ln (n + 2) + ln (n) - ln (n^{5})]

\frac{1}{3} lo g_{3} (8) + lo g_{3} (6) - lo g_{3} (3)

lo g_{3} (81 x^{3} 1 + x^{2})

- lo g_{10} (4.35 \cdot 1 0^{- 6})

What is log_{3}(3-x)+log_{3}(4-x) ?
The solution to log_{3}(3-x)+log_{3}(4-x) is log_{3}((3-x)(4-x))