What is log_{10}(y/(z^2)) ?

The solution to log_{10}(y/(z^2)) is log_{10}(y)-2log_{10}(z)

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simplify log_{10}(y/(z^2))

simplify

lo g_{10} (\frac{y}{z ^{2}})

lo g_{10} (y) - 2 lo g_{10} (z)

Solution steps

lo g_{10} (\frac{y}{z ^{2}})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{y}{z ^{2}}) = lo g_{10} (y) - lo g_{10} (z^{2})

= lo g_{10} (y) - lo g_{10} (z^{2})

Simplify

lo g_{10} (z^{2}) : 2 lo g_{10} (z)

= lo g_{10} (y) - 2 lo g_{10} (z)

\frac{1}{5} [20 ln (n + 2) + ln (n) - ln (n^{5})]

\frac{1}{3} lo g_{3} (8) + lo g_{3} (6) - lo g_{3} (3)

lo g_{3} (81 x^{3} 1 + x^{2})

- lo g_{10} (4.35 \cdot 1 0^{- 6})

ln (\frac{( 70 - 95 )}{( 5 - 95 ) ( 1.9958 )})

What is log_{10}(y/(z^2)) ?
The solution to log_{10}(y/(z^2)) is log_{10}(y)-2log_{10}(z)