What is log_{10}(2x-7)-log_{10}(x-1) ?

The solution to log_{10}(2x-7)-log_{10}(x-1) is log_{10}((2x-7)/(x-1))

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simplify log_{10}(2x-7)-log_{10}(x-1)

simplify

lo g_{10} (2 x - 7) - lo g_{10} (x - 1)

lo g_{10} (\frac{2 x - 7}{x - 1})

Solution steps

lo g_{10} (2 x - 7) - lo g_{10} (x - 1)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (2 x - 7) - lo g_{10} (x - 1) = lo g_{10} (\frac{2 x - 7}{x - 1})

= lo g_{10} (\frac{2 x - 7}{x - 1})

lo g_{b} (\frac{p ^{4} q ^{7}}{m ^{4} b ^{7}})

2 ln (5) + ln (6)

lo g_{3} (x) - lo g_{3} (x^{7})

lo g_{10} (\frac{1}{x ^{2} + 36})

What is log_{10}(2x-7)-log_{10}(x-1) ?
The solution to log_{10}(2x-7)-log_{10}(x-1) is log_{10}((2x-7)/(x-1))