What are the solutions to the equation 2x^2+5x+20=0 ?

The solutions to the equation 2x^2+5x+20=0 are x=-5/4+i(3sqrt(15))/4 ,x=-5/4-i(3sqrt(15))/4

Find the zeros of 2x^2+5x+20=0

The zeros of 2x^2+5x+20=0 are x=-5/4+i(3sqrt(15))/4 ,x=-5/4-i(3sqrt(15))/4

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2 x^{2} + 5 x + 20 = 0

x = - \frac{5}{4} + i \frac{3 15}{4}, x = - \frac{5}{4} - i \frac{3 15}{4}

Solution steps

2 x^{2} + 5 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

5^{2} - 4 \cdot 2 \cdot 20 : 315 i

x_{1, 2} = \frac{- 5 \pm 3 15 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 3 15 i}{2 \cdot 2}, x_{2} = \frac{- 5 - 3 15 i}{2 \cdot 2}

x = \frac{- 5 + 3 15 i}{2 \cdot 2} : - \frac{5}{4} + i \frac{3 15}{4}

x = \frac{- 5 - 3 15 i}{2 \cdot 2} : - \frac{5}{4} - i \frac{3 15}{4}

The solutions to the quadratic equation are:

x = - \frac{5}{4} + i \frac{3 15}{4}, x = - \frac{5}{4} - i \frac{3 15}{4}

x, z = x^{2} + y^{2}

x^{2} + 9 x - 13 = 0

x^{2} - 2 x

r, A = π r^{2}

- 2 x^{2} + 3 x - 5 = 0

What are the solutions to the equation 2x^2+5x+20=0 ?
The solutions to the equation 2x^2+5x+20=0 are x=-5/4+i(3sqrt(15))/4 ,x=-5/4-i(3sqrt(15))/4
Find the zeros of 2x^2+5x+20=0
The zeros of 2x^2+5x+20=0 are x=-5/4+i(3sqrt(15))/4 ,x=-5/4-i(3sqrt(15))/4