What are the solutions to the equation x^2+9x-13=0 ?

The solutions to the equation x^2+9x-13=0 are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2

Find the zeros of x^2+9x-13=0

The zeros of x^2+9x-13=0 are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2

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x^{2} + 9 x - 13 = 0

x = \frac{- 9 + 133}{2}, x = \frac{- 9 - 133}{2}

Decimal Notation

x = 1.26628 \dots, x = - 10.26628 \dots

Solution steps

x^{2} + 9 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 13) = 133

x_{1, 2} = \frac{- 9 \pm 133}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 133}{2 \cdot 1}, x_{2} = \frac{- 9 - 133}{2 \cdot 1}

x = \frac{- 9 + 133}{2 \cdot 1} : \frac{- 9 + 133}{2}

x = \frac{- 9 - 133}{2 \cdot 1} : \frac{- 9 - 133}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 133}{2}, x = \frac{- 9 - 133}{2}

x^{2} - 2 x

r, A = π r^{2}

- 2 x^{2} + 3 x - 5 = 0

r, V = \frac{1}{3} π r^{2} h

x^{2} - 12 x - 40 = 0

What are the solutions to the equation x^2+9x-13=0 ?
The solutions to the equation x^2+9x-13=0 are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2
Find the zeros of x^2+9x-13=0
The zeros of x^2+9x-13=0 are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2