What are the solutions to the equation x^2-12x-40=0 ?

The solutions to the equation x^2-12x-40=0 are x=2(3+sqrt(19)),x=2(3-sqrt(19))

Find the zeros of x^2-12x-40=0

The zeros of x^2-12x-40=0 are x=2(3+sqrt(19)),x=2(3-sqrt(19))

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x^{2} - 12 x - 40 = 0

x = 2 (3 + 19), x = 2 (3 - 19)

Decimal Notation

x = 14.71779 \dots, x = - 2.71779 \dots

Solution steps

x^{2} - 12 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 40) = 419

x_{1, 2} = \frac{- ( - 12 ) \pm 4 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 19}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 19}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 19}{2 \cdot 1} : 2 (3 + 19)

x = \frac{- ( - 12 ) - 4 19}{2 \cdot 1} : 2 (3 - 19)

The solutions to the quadratic equation are:

x = 2 (3 + 19), x = 2 (3 - 19)

r, x^{2} + y^{2} = r^{2}

x^{2} - 4 x

r, v = π r^{2} h

5 x^{2} - 60 x = 0

x^{2} + 6 x

What are the solutions to the equation x^2-12x-40=0 ?
The solutions to the equation x^2-12x-40=0 are x=2(3+sqrt(19)),x=2(3-sqrt(19))
Find the zeros of x^2-12x-40=0
The zeros of x^2-12x-40=0 are x=2(3+sqrt(19)),x=2(3-sqrt(19))