What are the solutions to the equation x^2+14x-5=0 ?

The solutions to the equation x^2+14x-5=0 are x=-7+3sqrt(6),x=-7-3sqrt(6)

Find the zeros of x^2+14x-5=0

The zeros of x^2+14x-5=0 are x=-7+3sqrt(6),x=-7-3sqrt(6)

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x^{2} + 14 x - 5 = 0

x = - 7 + 36, x = - 7 - 36

Decimal Notation

x = 0.34846 \dots, x = - 14.34846 \dots

Solution steps

x^{2} + 14 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 5) = 66

x_{1, 2} = \frac{- 14 \pm 6 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6 6}{2 \cdot 1}

x = \frac{- 14 + 6 6}{2 \cdot 1} : - 7 + 36

x = \frac{- 14 - 6 6}{2 \cdot 1} : - 7 - 36

The solutions to the quadratic equation are:

x = - 7 + 36, x = - 7 - 36

x, x^{2} + y^{2} + z^{2} = 1

x^{2} - 10 x

x, y^{2} = x^{2}

4 x^{2} - 20 x = - 21

x^{2} + 2 x + 2

What are the solutions to the equation x^2+14x-5=0 ?
The solutions to the equation x^2+14x-5=0 are x=-7+3sqrt(6),x=-7-3sqrt(6)
Find the zeros of x^2+14x-5=0
The zeros of x^2+14x-5=0 are x=-7+3sqrt(6),x=-7-3sqrt(6)