What are the solutions to the equation 4x^2-20x=-21 ?

The solutions to the equation 4x^2-20x=-21 are x= 7/2 ,x= 3/2

Find the zeros of 4x^2-20x=-21

The zeros of 4x^2-20x=-21 are x= 7/2 ,x= 3/2

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4 x^{2} - 20 x = - 21

x = \frac{7}{2}, x = \frac{3}{2}

Decimal Notation

x = 3.5, x = 1.5

Solution steps

4 x^{2} - 20 x = - 21

Move

21

to the left side

4 x^{2} - 20 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 21 = 8

x_{1, 2} = \frac{- ( - 20 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 8}{2 \cdot 4}

x = \frac{- ( - 20 ) + 8}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 20 ) - 8}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{3}{2}

x^{2} + 2 x + 2

12 x^{2} - 4 x = 0

x^{2} - 13 x - 30 = 0

15 x^{2} + 7 x - 2 = 0

25 (x + 2)^{2} = (x - 7)^{2} - 81

What are the solutions to the equation 4x^2-20x=-21 ?
The solutions to the equation 4x^2-20x=-21 are x= 7/2 ,x= 3/2
Find the zeros of 4x^2-20x=-21
The zeros of 4x^2-20x=-21 are x= 7/2 ,x= 3/2