What are the solutions to the equation 15x^2+7x-2=0 ?

The solutions to the equation 15x^2+7x-2=0 are x= 1/5 ,x=-2/3

Find the zeros of 15x^2+7x-2=0

The zeros of 15x^2+7x-2=0 are x= 1/5 ,x=-2/3

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15 x^{2} + 7 x - 2 = 0

x = \frac{1}{5}, x = - \frac{2}{3}

Decimal Notation

x = 0.2, x = - 0.66666 \dots

Solution steps

15 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 15 ( - 2 )}{2 \cdot 15}

7^{2} - 4 \cdot 15 (- 2) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 15}, x_{2} = \frac{- 7 - 13}{2 \cdot 15}

x = \frac{- 7 + 13}{2 \cdot 15} : \frac{1}{5}

x = \frac{- 7 - 13}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{2}{3}

25 (x + 2)^{2} = (x - 7)^{2} - 81

x^{2} - 3 x - 44 = - 3 x + 5

a, x^{2} + y^{2} = a^{2}

x^{2} + 2 x + 5

x^{2} + 7 = - 47

What are the solutions to the equation 15x^2+7x-2=0 ?
The solutions to the equation 15x^2+7x-2=0 are x= 1/5 ,x=-2/3
Find the zeros of 15x^2+7x-2=0
The zeros of 15x^2+7x-2=0 are x= 1/5 ,x=-2/3