What are the solutions to the equation x^2+10=11x ?

The solutions to the equation x^2+10=11x are x=10,x=1

Find the zeros of x^2+10=11x

The zeros of x^2+10=11x are x=10,x=1

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x^{2} + 10 = 11 x

x = 10, x = 1

Solution steps

x^{2} + 10 = 11 x

Move

11 x

to the left side

x^{2} + 10 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 11 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 10 = 9

x_{1, 2} = \frac{- ( - 11 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 9}{2 \cdot 1}

x = \frac{- ( - 11 ) + 9}{2 \cdot 1} : 10

x = \frac{- ( - 11 ) - 9}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 10, x = 1

x, z^{2} = x^{2} + y^{2}

(x + 6)^{2} = 25

\frac{2 x ^{2}}{5} + \frac{5 x}{4} = 10

a, c^{2} = a^{2} + b^{2}

x, 5 x^{2} - 2 x y + 2 y^{2} - 2 y - 71 = 0

What are the solutions to the equation x^2+10=11x ?
The solutions to the equation x^2+10=11x are x=10,x=1
Find the zeros of x^2+10=11x
The zeros of x^2+10=11x are x=10,x=1