What are the solutions to the equation completesquare x^2+4x+8 ?

The solutions to the equation completesquare x^2+4x+8 are (x+2)^2+4

Find the zeros of completesquare x^2+4x+8

The zeros of completesquare x^2+4x+8 are (x+2)^2+4

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complete the square

x^{2} + 4 x + 8

(x + 2)^{2} + 4

Solution steps

x^{2} + 4 x + 8

Write

x^{2} + 4 x + 8

in the form:

x^{2} + 2 a x + a^{2}

2 a = 4 : a = 2

Add and subtract

2^{2}

x^{2} + 4 x + 8 + 2^{2} - 2^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 4 x + 2^{2} = (x + 2)^{2}

(x + 2)^{2} + 8 - 2^{2}

Simplify

(x + 2)^{2} + 4

4 x^{2} - 28 x = - 53

2 x^{2} = 3

16 x^{2} - 64 x + 65 = 0

x^{2} + x + 1

v, E = \frac{1}{2} m v^{2}

What are the solutions to the equation completesquare x^2+4x+8 ?
The solutions to the equation completesquare x^2+4x+8 are (x+2)^2+4
Find the zeros of completesquare x^2+4x+8
The zeros of completesquare x^2+4x+8 are (x+2)^2+4