What are the solutions to the equation 2x^2=3 ?

The solutions to the equation 2x^2=3 are x=sqrt(3/2),x=-sqrt(3/2)

Find the zeros of 2x^2=3

The zeros of 2x^2=3 are x=sqrt(3/2),x=-sqrt(3/2)

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2 x^{2} = 3

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.22474 \dots, x = - 1.22474 \dots

Solution steps

2 x^{2} = 3

Divide both sides by

2

x^{2} = \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{2}, x = - \frac{3}{2}

16 x^{2} - 64 x + 65 = 0

x^{2} + x + 1

v, E = \frac{1}{2} m v^{2}

3 x^{2} + 2 x - 1

5 t^{2} - 20 t + 20 = 0

What are the solutions to the equation 2x^2=3 ?
The solutions to the equation 2x^2=3 are x=sqrt(3/2),x=-sqrt(3/2)
Find the zeros of 2x^2=3
The zeros of 2x^2=3 are x=sqrt(3/2),x=-sqrt(3/2)