What are the solutions to the equation -2x^2+10x-7=0 ?

The solutions to the equation -2x^2+10x-7=0 are x=(5-sqrt(11))/2 ,x=(5+sqrt(11))/2

Find the zeros of -2x^2+10x-7=0

The zeros of -2x^2+10x-7=0 are x=(5-sqrt(11))/2 ,x=(5+sqrt(11))/2

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- 2 x^{2} + 10 x - 7 = 0

x = \frac{5 - 11}{2}, x = \frac{5 + 11}{2}

Decimal Notation

x = 0.84168 \dots, x = 4.15831 \dots

Solution steps

- 2 x^{2} + 10 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

1 0^{2} - 4 (- 2) (- 7) = 211

x_{1, 2} = \frac{- 10 \pm 2 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 11}{2 ( - 2 )}, x_{2} = \frac{- 10 - 2 11}{2 ( - 2 )}

x = \frac{- 10 + 2 11}{2 ( - 2 )} : \frac{5 - 11}{2}

x = \frac{- 10 - 2 11}{2 ( - 2 )} : \frac{5 + 11}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 11}{2}, x = \frac{5 + 11}{2}

9 (2 x - 3)^{2} - 3 (3 - 2 x) - 6

∣ 1 - 5 x ∣ + 5 \geq 7

x^{2} + 98 = 0

\frac{1}{x - 7} + \frac{1}{x + 2} \geq \frac{2 x}{x ^{2} + x - 2}

4^{1}

What are the solutions to the equation -2x^2+10x-7=0 ?
The solutions to the equation -2x^2+10x-7=0 are x=(5-sqrt(11))/2 ,x=(5+sqrt(11))/2
Find the zeros of -2x^2+10x-7=0
The zeros of -2x^2+10x-7=0 are x=(5-sqrt(11))/2 ,x=(5+sqrt(11))/2