What is ax^2+bx+c=0,a=θ ?

The solution to ax^2+bx+c=0,a=θ is

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ax^2+bx+c=0,a=θ

a x^{2} + b x + c = 0, a = θ

(x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}, θ = a θ = a)

Solution steps

[a x^{2} + b x + c = 0 a = θ]

Solve

a = θ : θ = a

Plug the solutions

θ = a

into

a x^{2} + b x + c = 0

For

a x^{2} + b x + c = 0

, subsitute

θ

with

a : x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}; a \neq = 0

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

a x^{2} + b x + c = 0, a = θ

are

(x = \frac{- b + b ^{2} - 4 a c}{2 a}, x = \frac{- b - b ^{2} - 4 a c}{2 a}, θ = a θ = a)

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