What are the solutions to the equation -2x^2+23=7 ?

The solutions to the equation -2x^2+23=7 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of -2x^2+23=7

The zeros of -2x^2+23=7 are x=2sqrt(2),x=-2sqrt(2)

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- 2 x^{2} + 23 = 7

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

- 2 x^{2} + 23 = 7

Move

23

to the right side

- 2 x^{2} = - 16

Divide both sides by

- 2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

4 x^{2} = - 4 x - 17

s^{2} + 2 s + 5

- 3 x^{2} + 12 = 0

x^{2} = - 9 x + 8

3 y^{2} - 75 = 0

What are the solutions to the equation -2x^2+23=7 ?
The solutions to the equation -2x^2+23=7 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of -2x^2+23=7
The zeros of -2x^2+23=7 are x=2sqrt(2),x=-2sqrt(2)