What are the solutions to the equation -3x^2+12=0 ?

The solutions to the equation -3x^2+12=0 are x=2,x=-2

Find the zeros of -3x^2+12=0

The zeros of -3x^2+12=0 are x=2,x=-2

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- 3 x^{2} + 12 = 0

x = 2, x = - 2

Solution steps

- 3 x^{2} + 12 = 0

Move

12

to the right side

- 3 x^{2} = - 12

Divide both sides by

- 3

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} = - 9 x + 8

3 y^{2} - 75 = 0

x^{2} - \frac{5}{4} x + \frac{1}{4} = 0

7 x^{2} + 7 x - 84 = 0

x, x^{2} - x y + y^{2} = 3

What are the solutions to the equation -3x^2+12=0 ?
The solutions to the equation -3x^2+12=0 are x=2,x=-2
Find the zeros of -3x^2+12=0
The zeros of -3x^2+12=0 are x=2,x=-2