What are the solutions to the equation s^2+4s+8=0 ?

The solutions to the equation s^2+4s+8=0 are s=-2+2i,s=-2-2i

Find the zeros of s^2+4s+8=0

The zeros of s^2+4s+8=0 are s=-2+2i,s=-2-2i

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s^{2} + 4 s + 8 = 0

s = - 2 + 2 i, s = - 2 - 2 i

Solution steps

s^{2} + 4 s + 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 8 : 4 i

s_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 4 i}{2 \cdot 1}, s_{2} = \frac{- 4 - 4 i}{2 \cdot 1}

s = \frac{- 4 + 4 i}{2 \cdot 1} : - 2 + 2 i

s = \frac{- 4 - 4 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

s = - 2 + 2 i, s = - 2 - 2 i

x^{2} + 4 x + 3

x^{2} + 121 = - 22 x

2 x^{2} - 7.5 x + 7 = 0

(5 x - 4)^{2} - (3 x + 5) (2 x - 1) = 20 x (x - 2) + 27

2 x^{2} = 4

What are the solutions to the equation s^2+4s+8=0 ?
The solutions to the equation s^2+4s+8=0 are s=-2+2i,s=-2-2i
Find the zeros of s^2+4s+8=0
The zeros of s^2+4s+8=0 are s=-2+2i,s=-2-2i