What are the solutions to the equation 2x^2=4 ?

The solutions to the equation 2x^2=4 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 2x^2=4

The zeros of 2x^2=4 are x=sqrt(2),x=-sqrt(2)

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2 x^{2} = 4

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

2 x^{2} = 4

Divide both sides by

2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

r, v = \frac{1}{3} π r^{2}

x^{2} + 12 x + 45 = 0

12 x^{2} - 18 x = 0

x^{2} + 14 x = - 94

m^{2} + 4 m + 5 = 0

What are the solutions to the equation 2x^2=4 ?
The solutions to the equation 2x^2=4 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 2x^2=4
The zeros of 2x^2=4 are x=sqrt(2),x=-sqrt(2)