What are the solutions to the equation m^2+4m+5=0 ?

The solutions to the equation m^2+4m+5=0 are m=-2+i,m=-2-i

Find the zeros of m^2+4m+5=0

The zeros of m^2+4m+5=0 are m=-2+i,m=-2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 4 m + 5 = 0

m = - 2 + i, m = - 2 - i

Solution steps

m^{2} + 4 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

m_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

m = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

m = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

m = - 2 + i, m = - 2 - i

5 x^{2} + 4 = 2 (x + 2)

6 + 2 x^{2} = 20

x^{2} + 14 x

(x - 3)^{2} - (2 x + 5)^{2} = - 16

12 - x^{2} = - 3

What are the solutions to the equation m^2+4m+5=0 ?
The solutions to the equation m^2+4m+5=0 are m=-2+i,m=-2-i
Find the zeros of m^2+4m+5=0
The zeros of m^2+4m+5=0 are m=-2+i,m=-2-i