What are the solutions to the equation 6+2x^2=20 ?

The solutions to the equation 6+2x^2=20 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 6+2x^2=20

The zeros of 6+2x^2=20 are x=sqrt(7),x=-sqrt(7)

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6 + 2 x^{2} = 20

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

6 + 2 x^{2} = 20

Move

6

to the right side

2 x^{2} = 14

Divide both sides by

2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

x^{2} + 14 x

(x - 3)^{2} - (2 x + 5)^{2} = - 16

12 - x^{2} = - 3

x, x^{2} + x y + y^{2} = 3

4 x^{2} + 8 x + 13 = 0

What are the solutions to the equation 6+2x^2=20 ?
The solutions to the equation 6+2x^2=20 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 6+2x^2=20
The zeros of 6+2x^2=20 are x=sqrt(7),x=-sqrt(7)