What are the solutions to the equation 12-x^2=-3 ?

The solutions to the equation 12-x^2=-3 are x=sqrt(15),x=-sqrt(15)

Find the zeros of 12-x^2=-3

The zeros of 12-x^2=-3 are x=sqrt(15),x=-sqrt(15)

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12 - x^{2} = - 3

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

12 - x^{2} = - 3

Move

12

to the right side

- x^{2} = - 15

Divide both sides by

- 1

x^{2} = 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 15, x = - 15

x, x^{2} + x y + y^{2} = 3

4 x^{2} + 8 x + 13 = 0

12 x - 7 x^{2} + 64 = 0

4 x^{2} + 27 = x^{2}

4 x^{2} + 29 = - 12 x

What are the solutions to the equation 12-x^2=-3 ?
The solutions to the equation 12-x^2=-3 are x=sqrt(15),x=-sqrt(15)
Find the zeros of 12-x^2=-3
The zeros of 12-x^2=-3 are x=sqrt(15),x=-sqrt(15)