What are the solutions to the equation 12x-7x^2+64=0 ?

The solutions to the equation 12x-7x^2+64=0 are x=-16/7 ,x=4

Find the zeros of 12x-7x^2+64=0

The zeros of 12x-7x^2+64=0 are x=-16/7 ,x=4

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12 x - 7 x^{2} + 64 = 0

x = - \frac{16}{7}, x = 4

Decimal Notation

x = - 2.28571 \dots, x = 4

Solution steps

12 x - 7 x^{2} + 64 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} + 12 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 7 ) \cdot 64}{2 ( - 7 )}

1 2^{2} - 4 (- 7) \cdot 64 = 44

x_{1, 2} = \frac{- 12 \pm 44}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 12 + 44}{2 ( - 7 )}, x_{2} = \frac{- 12 - 44}{2 ( - 7 )}

x = \frac{- 12 + 44}{2 ( - 7 )} : - \frac{16}{7}

x = \frac{- 12 - 44}{2 ( - 7 )} : 4

The solutions to the quadratic equation are:

x = - \frac{16}{7}, x = 4

4 x^{2} + 27 = x^{2}

4 x^{2} + 29 = - 12 x

16 p^{2} - 8 p + 1 = 0

3 x^{2} + 2 x = 1

25 x^{2} + 90 x + 82 = 0

What are the solutions to the equation 12x-7x^2+64=0 ?
The solutions to the equation 12x-7x^2+64=0 are x=-16/7 ,x=4
Find the zeros of 12x-7x^2+64=0
The zeros of 12x-7x^2+64=0 are x=-16/7 ,x=4