What are the solutions to the equation x^2-4x+4=36 ?

The solutions to the equation x^2-4x+4=36 are x=8,x=-4

Find the zeros of x^2-4x+4=36

The zeros of x^2-4x+4=36 are x=8,x=-4

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x^{2} - 4 x + 4 = 36

x = 8, x = - 4

Solution steps

x^{2} - 4 x + 4 = 36

Move

36

to the left side

x^{2} - 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 1}

x = \frac{- ( - 4 ) + 12}{2 \cdot 1} : 8

x = \frac{- ( - 4 ) - 12}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

2 x^{2} + 11 x - 21 = 0

2 w^{2} - 16 w = 12 w - 48

1 3^{2} = 1 2^{2} + x^{2}

0 = 9 x^{2} - 10

x^{2} + 6 x - 18 = 0

What are the solutions to the equation x^2-4x+4=36 ?
The solutions to the equation x^2-4x+4=36 are x=8,x=-4
Find the zeros of x^2-4x+4=36
The zeros of x^2-4x+4=36 are x=8,x=-4