What are the solutions to the equation (x+3)^2=81 ?

The solutions to the equation (x+3)^2=81 are x=6,x=-12

Find the zeros of (x+3)^2=81

The zeros of (x+3)^2=81 are x=6,x=-12

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(x + 3)^{2} = 81

x = 6, x = - 12

Solution steps

(x + 3)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 81 : x = 6

Solve

x + 3 = - 81 : x = - 12

The solutions to the quadratic equation are:

x = 6, x = - 12

x, x^{2} + y^{2} = - 1

16 + 2 x^{2} = 30

x, x^{2} - y^{2} = 4 (x - y)

(x + 3) (x - 2) = 24

x, z = 4 - x^{2} - y^{2}

What are the solutions to the equation (x+3)^2=81 ?
The solutions to the equation (x+3)^2=81 are x=6,x=-12
Find the zeros of (x+3)^2=81
The zeros of (x+3)^2=81 are x=6,x=-12