What are the solutions to the equation solvefor x,x^2-y^2=4(x-y) ?

The solutions to the equation solvefor x,x^2-y^2=4(x-y) are x=y,x=-y+4

Find the zeros of solvefor x,x^2-y^2=4(x-y)

The zeros of solvefor x,x^2-y^2=4(x-y) are x=y,x=-y+4

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solve for

x, x^{2} - y^{2} = 4 (x - y)

x = y, x = - y + 4

Solution steps

x^{2} - y^{2} = 4 (x - y)

Expand

4 (x - y) : 4 x - 4 y

x^{2} - y^{2} = 4 x - 4 y

Move

4 y

to the left side

x^{2} - y^{2} + 4 y = 4 x

Move

4 x

to the left side

x^{2} - y^{2} + 4 y - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - y^{2} + 4 y = 0

Factor

x^{2} - 4 x - y^{2} + 4 y : (x - y) (x + y - 4)

(x - y) (x + y - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - y = 0 or x + y - 4 = 0

Solve

x - y = 0 : x = y

Solve

x + y - 4 = 0 : x = - y + 4

The solutions to the quadratic equation are:

x = y, x = - y + 4

(x + 3) (x - 2) = 24

x, z = 4 - x^{2} - y^{2}

2 x^{2} + 6 x - 80 = 0

x, x^{2} + 2 x y - 4 + y^{2} = 0

(x + 4)^{2} = 63

What are the solutions to the equation solvefor x,x^2-y^2=4(x-y) ?
The solutions to the equation solvefor x,x^2-y^2=4(x-y) are x=y,x=-y+4
Find the zeros of solvefor x,x^2-y^2=4(x-y)
The zeros of solvefor x,x^2-y^2=4(x-y) are x=y,x=-y+4