What are the solutions to the equation (x+4)^2=63 ?

The solutions to the equation (x+4)^2=63 are x=3sqrt(7)-4,x=-3sqrt(7)-4

Find the zeros of (x+4)^2=63

The zeros of (x+4)^2=63 are x=3sqrt(7)-4,x=-3sqrt(7)-4

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(x + 4)^{2} = 63

x = 37 - 4, x = - 37 - 4

Decimal Notation

x = 3.93725 \dots, x = - 11.93725 \dots

Solution steps

(x + 4)^{2} = 63

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 63 : x = 37 - 4

Solve

x + 4 = - 63 : x = - 37 - 4

The solutions to the quadratic equation are:

x = 37 - 4, x = - 37 - 4

x, - 5 x^{2} + 60 x + 7 y^{2} + 84 y + 72 = 0

3 x^{2} - 5 x + 8 = 0

(2 x - 3)^{2} = 169

x^{2} - 12 x + 100 = 0

14 + 2 x^{2} = 22

What are the solutions to the equation (x+4)^2=63 ?
The solutions to the equation (x+4)^2=63 are x=3sqrt(7)-4,x=-3sqrt(7)-4
Find the zeros of (x+4)^2=63
The zeros of (x+4)^2=63 are x=3sqrt(7)-4,x=-3sqrt(7)-4