What are the solutions to the equation 3x^2-5x+8=0 ?

The solutions to the equation 3x^2-5x+8=0 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6

Find the zeros of 3x^2-5x+8=0

The zeros of 3x^2-5x+8=0 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 5 x + 8 = 0

x = \frac{5}{6} + i \frac{71}{6}, x = \frac{5}{6} - i \frac{71}{6}

Solution steps

3 x^{2} - 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 8 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 3} : \frac{5}{6} + i \frac{71}{6}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 3} : \frac{5}{6} - i \frac{71}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{71}{6}, x = \frac{5}{6} - i \frac{71}{6}

(2 x - 3)^{2} = 169

x^{2} - 12 x + 100 = 0

14 + 2 x^{2} = 22

- 2 x^{2} + 6 x - 3 = 0

x, x^{2} - 9 y^{2} + 2 x - 54 y - 80 = 0

What are the solutions to the equation 3x^2-5x+8=0 ?
The solutions to the equation 3x^2-5x+8=0 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6
Find the zeros of 3x^2-5x+8=0
The zeros of 3x^2-5x+8=0 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6