What are the solutions to the equation 6y^2+22y+12=5y ?

The solutions to the equation 6y^2+22y+12=5y are y=-4/3 ,y=-3/2

Find the zeros of 6y^2+22y+12=5y

The zeros of 6y^2+22y+12=5y are y=-4/3 ,y=-3/2

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6 y^{2} + 22 y + 12 = 5 y

y = - \frac{4}{3}, y = - \frac{3}{2}

Decimal Notation

y = - 1.33333 \dots, y = - 1.5

Solution steps

6 y^{2} + 22 y + 12 = 5 y

Move

5 y

to the left side

6 y^{2} + 17 y + 12 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 12}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 12 = 1

y_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- 17 + 1}{2 \cdot 6}, y_{2} = \frac{- 17 - 1}{2 \cdot 6}

y = \frac{- 17 + 1}{2 \cdot 6} : - \frac{4}{3}

y = \frac{- 17 - 1}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

y = - \frac{4}{3}, y = - \frac{3}{2}

3 x^{2} - 10 x + 1 = 0

x^{2} - 16 x

(4 x - 1) (2 x + 3) = (x + 3) (x - 1)

(m + 8)^{2} = 72

5 r^{2} - 20 r + 15 = 0

What are the solutions to the equation 6y^2+22y+12=5y ?
The solutions to the equation 6y^2+22y+12=5y are y=-4/3 ,y=-3/2
Find the zeros of 6y^2+22y+12=5y
The zeros of 6y^2+22y+12=5y are y=-4/3 ,y=-3/2