What are the solutions to the equation -6x^2+103x-17=0 ?

The solutions to the equation -6x^2+103x-17=0 are x= 1/6 ,x=17

Find the zeros of -6x^2+103x-17=0

The zeros of -6x^2+103x-17=0 are x= 1/6 ,x=17

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- 6 x^{2} + 103 x - 17 = 0

x = \frac{1}{6}, x = 17

Decimal Notation

x = 0.16666 \dots, x = 17

Solution steps

- 6 x^{2} + 103 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 103 \pm 10 3 ^{2} - 4 ( - 6 ) ( - 17 )}{2 ( - 6 )}

10 3^{2} - 4 (- 6) (- 17) = 101

x_{1, 2} = \frac{- 103 \pm 101}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 103 + 101}{2 ( - 6 )}, x_{2} = \frac{- 103 - 101}{2 ( - 6 )}

x = \frac{- 103 + 101}{2 ( - 6 )} : \frac{1}{6}

x = \frac{- 103 - 101}{2 ( - 6 )} : 17

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = 17

n^{2} - 6 = - n

2 x^{2} + 11 = 131

w^{2} - \frac{1}{15} w = \frac{2}{15}

x^{2} + 5 x

x, y^{3} = x^{2}

What are the solutions to the equation -6x^2+103x-17=0 ?
The solutions to the equation -6x^2+103x-17=0 are x= 1/6 ,x=17
Find the zeros of -6x^2+103x-17=0
The zeros of -6x^2+103x-17=0 are x= 1/6 ,x=17