What are the solutions to the equation 5(x-7)^2+27=32 ?

The solutions to the equation 5(x-7)^2+27=32 are x=8,x=6

Find the zeros of 5(x-7)^2+27=32

The zeros of 5(x-7)^2+27=32 are x=8,x=6

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5 (x - 7)^{2} + 27 = 32

x = 8, x = 6

Solution steps

5 (x - 7)^{2} + 27 = 32

Move

27

to the right side

5 (x - 7)^{2} = 5

Divide both sides by

5

(x - 7)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 1 : x = 8

Solve

x - 7 = - 1 : x = 6

The solutions to the quadratic equation are:

x = 8, x = 6

2 x^{2} - x + 5 = 0

2 x^{2} - 4 x + 10 = 0

2 x^{2} - x + 55 = (x + 5)^{2}

5 x^{2} - 3 x = 0

m^{2} - 5 m = 0

What are the solutions to the equation 5(x-7)^2+27=32 ?
The solutions to the equation 5(x-7)^2+27=32 are x=8,x=6
Find the zeros of 5(x-7)^2+27=32
The zeros of 5(x-7)^2+27=32 are x=8,x=6