What are the solutions to the equation m^2-5m=0 ?

The solutions to the equation m^2-5m=0 are m=5,m=0

Find the zeros of m^2-5m=0

The zeros of m^2-5m=0 are m=5,m=0

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m^{2} - 5 m = 0

m = 5, m = 0

Solution steps

m^{2} - 5 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

m_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, m_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

m = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

m = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 5, m = 0

5 (y + 3) - 5 (y^{2} - 1) = y^{2} + 7 (3 - y) - 1

- 3 x^{2} + x - 3 = 0

(z - 6)^{2} = 25

6 x^{2} + 10 x - 4 = 0

x^{2} - 20 x + 12 = 0

What are the solutions to the equation m^2-5m=0 ?
The solutions to the equation m^2-5m=0 are m=5,m=0
Find the zeros of m^2-5m=0
The zeros of m^2-5m=0 are m=5,m=0