What are the solutions to the equation x^2+37=-14x ?

The solutions to the equation x^2+37=-14x are x=-7+2sqrt(3),x=-7-2sqrt(3)

Find the zeros of x^2+37=-14x

The zeros of x^2+37=-14x are x=-7+2sqrt(3),x=-7-2sqrt(3)

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x^{2} + 37 = - 14 x

x = - 7 + 23, x = - 7 - 23

Decimal Notation

x = - 3.53589 \dots, x = - 10.46410 \dots

Solution steps

x^{2} + 37 = - 14 x

Move

14 x

to the left side

x^{2} + 37 + 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 14 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 37 = 43

x_{1, 2} = \frac{- 14 \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 3}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 3}{2 \cdot 1}

x = \frac{- 14 + 4 3}{2 \cdot 1} : - 7 + 23

x = \frac{- 14 - 4 3}{2 \cdot 1} : - 7 - 23

The solutions to the quadratic equation are:

x = - 7 + 23, x = - 7 - 23

m^{2} + 10 m + 21 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 18 x

6 x^{2} - 2 = 0

2 (x^{2} + 5) - 7 = 7

What are the solutions to the equation x^2+37=-14x ?
The solutions to the equation x^2+37=-14x are x=-7+2sqrt(3),x=-7-2sqrt(3)
Find the zeros of x^2+37=-14x
The zeros of x^2+37=-14x are x=-7+2sqrt(3),x=-7-2sqrt(3)