What are the solutions to the equation -2x^2+10x-3=0 ?

The solutions to the equation -2x^2+10x-3=0 are x=(5-sqrt(19))/2 ,x=(5+sqrt(19))/2

Find the zeros of -2x^2+10x-3=0

The zeros of -2x^2+10x-3=0 are x=(5-sqrt(19))/2 ,x=(5+sqrt(19))/2

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- 2 x^{2} + 10 x - 3 = 0

x = \frac{5 - 19}{2}, x = \frac{5 + 19}{2}

Decimal Notation

x = 0.32055 \dots, x = 4.67944 \dots

Solution steps

- 2 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

1 0^{2} - 4 (- 2) (- 3) = 219

x_{1, 2} = \frac{- 10 \pm 2 19}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 19}{2 ( - 2 )}, x_{2} = \frac{- 10 - 2 19}{2 ( - 2 )}

x = \frac{- 10 + 2 19}{2 ( - 2 )} : \frac{5 - 19}{2}

x = \frac{- 10 - 2 19}{2 ( - 2 )} : \frac{5 + 19}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 19}{2}, x = \frac{5 + 19}{2}

x^{2} + 16 x = - 55

6 x^{2} - 12 x + 1 = 0

x^{2} + 7 = 88

x^{2} + 10 = 7 x

x^{2} - 16 x = - 100

What are the solutions to the equation -2x^2+10x-3=0 ?
The solutions to the equation -2x^2+10x-3=0 are x=(5-sqrt(19))/2 ,x=(5+sqrt(19))/2
Find the zeros of -2x^2+10x-3=0
The zeros of -2x^2+10x-3=0 are x=(5-sqrt(19))/2 ,x=(5+sqrt(19))/2