What are the solutions to the equation 6x^2-12x+1=0 ?

The solutions to the equation 6x^2-12x+1=0 are x=(6+sqrt(30))/6 ,x=(6-sqrt(30))/6

Find the zeros of 6x^2-12x+1=0

The zeros of 6x^2-12x+1=0 are x=(6+sqrt(30))/6 ,x=(6-sqrt(30))/6

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6 x^{2} - 12 x + 1 = 0

x = \frac{6 + 30}{6}, x = \frac{6 - 30}{6}

Decimal Notation

x = 1.91287 \dots, x = 0.08712 \dots

Solution steps

6 x^{2} - 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 1 = 230

x_{1, 2} = \frac{- ( - 12 ) \pm 2 30}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 30}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 2 30}{2 \cdot 6}

x = \frac{- ( - 12 ) + 2 30}{2 \cdot 6} : \frac{6 + 30}{6}

x = \frac{- ( - 12 ) - 2 30}{2 \cdot 6} : \frac{6 - 30}{6}

The solutions to the quadratic equation are:

x = \frac{6 + 30}{6}, x = \frac{6 - 30}{6}

x^{2} + 7 = 88

x^{2} + 10 = 7 x

x^{2} - 16 x = - 100

2 (x - 9)^{2} + 13 = 21

x^{2} + 4 x + 4 = 10

What are the solutions to the equation 6x^2-12x+1=0 ?
The solutions to the equation 6x^2-12x+1=0 are x=(6+sqrt(30))/6 ,x=(6-sqrt(30))/6
Find the zeros of 6x^2-12x+1=0
The zeros of 6x^2-12x+1=0 are x=(6+sqrt(30))/6 ,x=(6-sqrt(30))/6