What are the solutions to the equation 2(x-9)^2+13=21 ?

The solutions to the equation 2(x-9)^2+13=21 are x=11,x=7

Find the zeros of 2(x-9)^2+13=21

The zeros of 2(x-9)^2+13=21 are x=11,x=7

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2 (x - 9)^{2} + 13 = 21

x = 11, x = 7

Solution steps

2 (x - 9)^{2} + 13 = 21

Move

13

to the right side

2 (x - 9)^{2} = 8

Divide both sides by

2

(x - 9)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 4 : x = 11

Solve

x - 9 = - 4 : x = 7

The solutions to the quadratic equation are:

x = 11, x = 7

x^{2} + 4 x + 4 = 10

a, - 32 a w - 15 a^{2} = - 7 w^{2}

3 x^{2} + 8 x + 8 = 4

(x - 9)^{2} + 26 = 31

r, A = 4 π r^{2}

What are the solutions to the equation 2(x-9)^2+13=21 ?
The solutions to the equation 2(x-9)^2+13=21 are x=11,x=7
Find the zeros of 2(x-9)^2+13=21
The zeros of 2(x-9)^2+13=21 are x=11,x=7