What are the solutions to the equation x^2+2x+32=0 ?

The solutions to the equation x^2+2x+32=0 are x=-1+sqrt(31)i,x=-1-sqrt(31)i

Find the zeros of x^2+2x+32=0

The zeros of x^2+2x+32=0 are x=-1+sqrt(31)i,x=-1-sqrt(31)i

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x^{2} + 2 x + 32 = 0

x = - 1 + 31 i, x = - 1 - 31 i

Solution steps

x^{2} + 2 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 32 : 231 i

x_{1, 2} = \frac{- 2 \pm 2 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 31 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 31 i}{2 \cdot 1}

x = \frac{- 2 + 2 31 i}{2 \cdot 1} : - 1 + 31 i

x = \frac{- 2 - 2 31 i}{2 \cdot 1} : - 1 - 31 i

The solutions to the quadratic equation are:

x = - 1 + 31 i, x = - 1 - 31 i

5 (x - 6)^{2} - 29 = - 19

4 x^{2} + 89 = 36 x

x^{2} + 14 x = - 45

5 x^{2} = 3 x + 2

4 (x - 2)^{2} = 16

What are the solutions to the equation x^2+2x+32=0 ?
The solutions to the equation x^2+2x+32=0 are x=-1+sqrt(31)i,x=-1-sqrt(31)i
Find the zeros of x^2+2x+32=0
The zeros of x^2+2x+32=0 are x=-1+sqrt(31)i,x=-1-sqrt(31)i