What are the solutions to the equation completesquare x^2+2x-4=0 ?

The solutions to the equation completesquare x^2+2x-4=0 are x=sqrt(5)-1,x=-sqrt(5)-1

Find the zeros of completesquare x^2+2x-4=0

The zeros of completesquare x^2+2x-4=0 are x=sqrt(5)-1,x=-sqrt(5)-1

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x^{2} + 2 x - 4 = 0

x = 5 - 1, x = - 5 - 1

Decimal

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

x^{2} + 2 x - 4 = 0

Move

4

to the right side

x^{2} + 2 x = 4

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = 5

For

the solutions are

f (x) = a, - a

Solve

x + 1 = 5 : x = 5 - 1

Solve

x + 1 = - 5 : x = - 5 - 1

The solutions to the quadratic equation are:

x = 5 - 1, x = - 5 - 1

12 - 3 x^{2} = 0

x, x^{2} = y^{3}

x, 4 x^{2} + 3 x y - 4 y^{2} - 12 x - 18 y + 4 = 0

3 (x - 8)^{2} - 34 = - 7

x^{2} + 8 x + 6

What are the solutions to the equation completesquare x^2+2x-4=0 ?
The solutions to the equation completesquare x^2+2x-4=0 are x=sqrt(5)-1,x=-sqrt(5)-1
Find the zeros of completesquare x^2+2x-4=0
The zeros of completesquare x^2+2x-4=0 are x=sqrt(5)-1,x=-sqrt(5)-1