What are the solutions to the equation z^2=-1 ?

The solutions to the equation z^2=-1 are z=i,z=-i

Find the zeros of z^2=-1

The zeros of z^2=-1 are z=i,z=-i

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z^{2} = - 1

z = i, z = - i

Solution steps

z^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 1, z = - - 1

- 1 = i

- - 1 = - i

z = i, z = - i

x^{2} = 5^{2} + 1 2^{2}

x^{2} - 289 = 0

4 (x + 7)^{2} - 49 = - 13

x^{2} - 6 x + 9 = 256

7 x = 15 - 30 x^{2}

What are the solutions to the equation z^2=-1 ?
The solutions to the equation z^2=-1 are z=i,z=-i
Find the zeros of z^2=-1
The zeros of z^2=-1 are z=i,z=-i