What are the solutions to the equation z^2-5=-4 ?

The solutions to the equation z^2-5=-4 are z=1,z=-1

Find the zeros of z^2-5=-4

The zeros of z^2-5=-4 are z=1,z=-1

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z^{2} - 5 = - 4

z = 1, z = - 1

Solution steps

z^{2} - 5 = - 4

Move

5

to the right side

z^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 1, z = - 1

1 = 1

- 1 = - 1

z = 1, z = - 1

(x + 3)^{2} - 13 = - 4

- 3 x^{2} - 10 x + 8 = 0

36 x^{2} - 24 x - 24 = 0

4 (x - 9)^{2} - 15 = 25

- 5 x^{2} - 30 x - 365 = 0

What are the solutions to the equation z^2-5=-4 ?
The solutions to the equation z^2-5=-4 are z=1,z=-1
Find the zeros of z^2-5=-4
The zeros of z^2-5=-4 are z=1,z=-1