What are the solutions to the equation 4(x-9)^2-15=25 ?

The solutions to the equation 4(x-9)^2-15=25 are x=sqrt(10)+9,x=-sqrt(10)+9

Find the zeros of 4(x-9)^2-15=25

The zeros of 4(x-9)^2-15=25 are x=sqrt(10)+9,x=-sqrt(10)+9

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4 (x - 9)^{2} - 15 = 25

x = 10 + 9, x = - 10 + 9

Decimal Notation

x = 12.16227 \dots, x = 5.83772 \dots

Solution steps

4 (x - 9)^{2} - 15 = 25

Move

15

to the right side

4 (x - 9)^{2} = 40

Divide both sides by

4

(x - 9)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 10 : x = 10 + 9

Solve

x - 9 = - 10 : x = - 10 + 9

The solutions to the quadratic equation are:

x = 10 + 9, x = - 10 + 9

- 5 x^{2} - 30 x - 365 = 0

12 x^{2} - 120 x + 209 = 0

63 z^{2} + 61 z = - 6

4 x^{2} - 2 x - 3 = 2 x

x^{2} + 9 x - 83 = 4 x + 1

What are the solutions to the equation 4(x-9)^2-15=25 ?
The solutions to the equation 4(x-9)^2-15=25 are x=sqrt(10)+9,x=-sqrt(10)+9
Find the zeros of 4(x-9)^2-15=25
The zeros of 4(x-9)^2-15=25 are x=sqrt(10)+9,x=-sqrt(10)+9