What are the solutions to the equation x^2+9x-83=4x+1 ?

The solutions to the equation x^2+9x-83=4x+1 are x=7,x=-12

Find the zeros of x^2+9x-83=4x+1

The zeros of x^2+9x-83=4x+1 are x=7,x=-12

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x^{2} + 9 x - 83 = 4 x + 1

x = 7, x = - 12

Solution steps

x^{2} + 9 x - 83 = 4 x + 1

Move

1

to the left side

x^{2} + 9 x - 84 = 4 x

Move

4 x

to the left side

x^{2} + 5 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 84 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 84) = 19

x_{1, 2} = \frac{- 5 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 19}{2 \cdot 1}, x_{2} = \frac{- 5 - 19}{2 \cdot 1}

x = \frac{- 5 + 19}{2 \cdot 1} : 7

x = \frac{- 5 - 19}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 7, x = - 12

4 x^{2} - 10 x = 0

2 x^{2} + x - 11 = 6 x - 8

x^{2} + 20 x + 101 = 0

x^{2} + 118 = 20 x

a x^{2} + b x + c

What are the solutions to the equation x^2+9x-83=4x+1 ?
The solutions to the equation x^2+9x-83=4x+1 are x=7,x=-12
Find the zeros of x^2+9x-83=4x+1
The zeros of x^2+9x-83=4x+1 are x=7,x=-12